Batch files (cmd) : removing last "\" in directory name [closed]-CodePudding

I write some .bat files. In them, I need to get the current directory without the remaining "\". I use this kind of script :

@ECHO OFF
SET ROOT_DIR=%~dp0
@ECHO ROOT_DIR IS "%ROOT_DIR%"
REM Remove last "\"
if "%ROOT_DIR:~-1%" == "\" (
  SET ROOT_DIR=%ROOT_DIR:~0,-1%
)
@ECHO ADAPTED ROOT_DIR IS "%ROOT_DIR%"
PAUSE

It generally works. For example, if I put such a file in D:\test, the result is :

ROOT_DIR IS "D:\test\"
ADAPTED ROOT_DIR IS "D:\test"
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However, for some reason I don't understand, there is a problem when the folder name ends with ")", like "C:\Program Files (x86)". In that folder, it removes the last ")" too, which is a behaviour I don't want :

ROOT_DIR IS "C:\Program Files (x86)\"
ADAPTED ROOT_DIR IS "C:\Program Files (x86"
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Does anyone have any idea about how to solve that problem, i.e. removing only the last "\" in folder name, whatever the folder name, and without removing the parenthesis ?

Thank you by advance for your answers.

CodePudding user response：

@Mofi had the right answer : I should use quotes around the SET ROOT_DIR instructions. That way, the parenthesis are kept (no interpretation). I tested on various folders and it did work. So thank you very much @Mofi for the solution.

And thank you @phuclv concerning "DOS batch file", I will keep that in mind (I updated the title).

--Edit--

So the right code becomes

@ECHO OFF
SET "ROOT_DIR=%~dp0"
@ECHO ROOT_DIR IS "%ROOT_DIR%"
REM Remove last "\"
if "%ROOT_DIR:~-1%" == "\" (
  SET "ROOT_DIR=%ROOT_DIR:~0,-1%"
)
@ECHO ADAPTED ROOT_DIR IS "%ROOT_DIR%"
PAUSE

This kind of code is a base to then use recursive algorithms that will enter sub-directories (sub-sub-directories and so on) by adding "\" then sub-directory name and do that at any desired depth. So, in my case, it is useful even when the parent directory is directly the drive letter itself.