I am not sure if this kind of questions are appropriate here, but... By changing (or adding) one character make this program print '*' exactly 20 times

void main(){
   int i, n=20;
   for (i=0; i<n; i--)
      printf("*");
}

Any ideas?

CodePudding user response：

It seems you mean the following change from

for (i=0; i<n; i--)
              ^^^ 

to

for (i=0; i<n; n--)
              ^^^

Here is one character i is substituted for one character n.

Another way (if it is allowed by the puzzle) is to add one character '-' like

for (i=0; -i<n; i--)
         ^^^

Note: By the way pay attention to that according to the C Standard the function main without parameters shall be declared like :)

int main( void )

CodePudding user response：

either do i or (i-- & n-=2or any other positive number greater the 1)