test.dat <- c("abcde", "abcXe", "abcdY", "abcXY")
test.want <- c("abcde", "abc1Xe", "abcd1Y", "abc1XY")
Suppose I wish to add "1" before "X" or "Y", and before "X" if both "X" and "Y" exist.
library(tidyverse)
case_when(
str_detect(test.dat, "X") ~ str_replace(test.dat, "X", "1X"),
str_detect(test.dat, "Y") ~ str_replace(test.dat, "Y", "1Y"),
TRUE ~ as.character(test.dat)
)
This works but is there a better way to do this in concise manner? Perhaps in single str_replace
?
How about if it was either "X" or "Y" whichever comes first?
stringr is preferable but I welcome any other methods. Thank you.
CodePudding user response:
You can use a look ahead with (?=X)
for X
and (?=Y)
for Y
and make the decission if there is an X
with ifelse
and grepl
.
test.dat <- c("abcde", "abcXe", "abcdY", "abcXY", "abYcXY")
ifelse(grepl("X", test.dat)
, sub("(?=X)", "1", test.dat, perl=TRUE)
, sub("(?=Y)", "1", test.dat, perl=TRUE))
#[1] "abcde" "abc1Xe" "abcd1Y" "abc1XY" "abYc1XY"
or
sub("(?=X)|(?=Y)(?!.*X)", "1", test.dat, perl=TRUE)
#[1] "abcde" "abc1Xe" "abcd1Y" "abc1XY" "abYc1XY"
CodePudding user response:
You can use
test.dat <- c("abcde", "abcXe", "abcdY", "abcXY")
gsub("(XY?|Y)", "1\\1", test.dat)
# => [1] "abcde" "abc1Xe" "abcd1Y" "abc1XY"
See the regex demo.
Here, (XY?|Y)
matches and captures into Group 1 (\1
) an X
and an optional Y
after it (with XY?
), or (|
) a Y
char, and then all found matches are replaced with 1
and Group 1 value.
stringr
version is
library(stringr)
str_replace_all(test.dat, "(XY?|Y)", "1\\1")
See the online R demo.