how to replace continuous pattern in text-CodePudding

i have text like 1|2|3||| , and try to replace each || with |0|, my command is following

      echo  '1|2|3|||'  | sed -e 's/||/|0|/g'

but get result 1|2|3|0||, the pattern is only replaced once.

could someone help me improve the command, thx

CodePudding user response：

Just do it 2 times

l_replace='s#||#|0|#g'
echo  '1|2|3||||||||4||5|||'  | sed -e "$l_replace;$l_replace"

CodePudding user response：

This might work for you (GNU sed):

sed 's/||/|0|/g;s//[0]/g' file

or:

sed ':a;s/||/|0|/g;ta' file

The replacement needs to actioned twice because part of the match is in the replacement.

CodePudding user response：

Using any sed or any awk in any shell on every Unix box:

$ echo  '1|2|3|||'  | sed -e 's/||/|0|/g; s/||/|0|/g'
1|2|3|0|0|

$ echo  '1|2|3|||'  | awk '{while(gsub(/\|\|/,"|0|"))l}1'
1|2|3|0|0|