this my situation at the moment: I save a dynamic string into a variable $content.
With this code I get all values of my $content which has the number format x.xx
preg_match_all('/\d \,\d /m', $content, $matches);
Now I would like to get additionally all values which are dates. For example:
14.10.2021
10/14/2021
10. October 2021
The year could be also like 21 instead of 2021. Here are many version possible.
Is there also a preg_match_all solution for that? Or is there an way to say:
Give me all values of the string, where php found a valid date?
Thank you a lot !!
CodePudding user response：
Using the DateTime class is generally a good idea to work with dates but I guess that you need to extract them as your string does not only contain dates.
Using a RegEx results in long patterns because of months:
\d{2}(\.|\/)?(\d{2}\1|\s(January|February|March|April|May|June|July|August|September|October|November|December)\s)(\d{4}|\d{2})
But it matches the following:
\d{2}2 digits(\.|\/)?an optional dot or slash (group capture n°1)(\d{2}\12 digits followed by group capture n°1|or\s(January|February|March|April|May|June|July|August|September|October|November|December)\sa month with spaces around
)(\d{4}|\d{2})2 or 4 digits