I have a list of item List<Item> resultBl
like below :
id = 18003 amount = 128 nameType = SUBMITTED
id = 18189 amount = 95 nameType = SUBMITTED
id = 18192 amount = 160 nameType = POSITIVE
id = 18192 amount = 30 nameType = DRAFT
id = 18192 amount = 873 nameType = SUBMITTED
id = 18237 amount = 390 nameType = POSITIVE
id = 18237 amount = 60 nameType = DRAFT
id = 18237 amount = 2731 nameType = SUBMITTED
I want to transform this list to a map
with this form, the key is the id
and the value is a list
of objects :
Map<Integer,List<ItemDetails>> mapTest= new HashMap<Integer,List<ItemDetails>>();
[18237 , [amount = 390 ,nameType = POSITIVE],[amount = 60 nameType = DRAFT], [amount = 2731 nameType = SUBMITTED]], ...
I tried with different ways but always I had a repeated elements :
List<Integer> ids2 = new ArrayList<Integer>();
List<Integer> ids = new ArrayList<Integer>();
for(Item item: resultBl) {
ids.add(item.getId());
}
ids2 =ids.stream().distinct().collect(Collectors.toList());
Map<Integer,List<ItemDetails>> mapTest= new HashMap<Integer,List<ItemDetails>>();
List<ItemDetails> itemDetailsList = new ArrayList<ItemDetails>();
for(Integer s:ids2) {
for(Item i : resultBl) {
if(s.equals(i.getId())) {
ItemDetails it =new ItemDetails();
it.setAmount(i.getAmount());
it.setNameType(i.getNameType()) ;
itemDetailsList .add(it);
}
}
mapTest.put(s, itemDetailsList);
}
CodePudding user response:
I would use streams and groupingBy
to do this.
When you have a list of your items resultBl
all you have to do is
Map<Integer, List<Item>> resultMap = resultBl.stream().collect(groupingBy(Item::getId, toList()));
imports:
import static java.util.stream.Collectors.groupingBy;
import static java.util.stream.Collectors.toList;
This will group your items by the id
parameter.
CodePudding user response:
Map<Integer,List<Item>> map = resultBL.stream(Collectors.toMap(Item::getId, Function.identity()));
It is Lambda. Java version >= 8