Why is my python code giving wrong answers for only some inputs?-CodePudding

I am new to python and I was trying to write a program that gives the frequency of each letters in a string from a specific point. Now my code is giving correct output for some inputs like if I give the input "hheelloo", I get the correct output, but if the input is "hheelllloooo", the frequency of h,e and l is printed correct, but the frequency of 'o' comes out as 7 if the starting point is index 0. Can somebody tell me what am i doing wrong.

Write a Python program that counts the occurrence of Character in a String (Do not use built in count function. Modify the above program so that it starts counting from Specified Location.

str = list(map(str, input("Enter the string : ")))
count = 1
c = int(input("Enter the location from which the count needs to start : "))
for i in range(c, len(str)):
    for j in range(i 1,len(str)):
        if str[i] == str[j]:
            count  = 1
            str[j] = 0
    if str[i] != 0:
        print(str[i], " appears ", count, " times")
        count = 1

CodePudding user response：

str = list(map(str, input("Enter the string : ")))
count = 1
c = int(input("Enter the location from which the count needs to start : "))
for i in range(c, len(str)):
    for j in range(i 1,len(str)):
        if str[i] == str[j]:
            count  = 1
            str[j] = 0
    if str[i] != 0:
        print(str[i], " appears ", count, " times")
    count = 1 // <----- This line should be outside the if block.

The error was because of indentation. I have just properly indented the last line.

Thanks, if it works, kindly upvote.

CodePudding user response：

string module can be useful and easy to calculate the frequency of letters, numbers and special characters in a string.

import string

a='aahdhdhhhh2236665111...//// '

for i in string.printable:
    z=0
    for j in a:
        if i==j:
            z =1
    if z!=0:
        print(f'{i} occurs in the string a {z} times')

If you want to calculate the frequency of characters from a particular index value, you just have to modify the above code a little as follows:

import string

a='aahdhdhhhh2236665111...//// '
c = int(input("Enter the location from which the count needs to start : "))
for i in string.printable:
    z=0
    for j in a[c:]:
        if i==j:
            z =1
    if z!=0:
        print(f'{i} occurs in the string a {z} times')