(Better title wording recommendations welcome)
pacman::p_load(tidyverse, fable, fpp3, feasts)
aus_livestock$Month |> max() |> as_date()
[1] "2018-12-01"
I want to get this date minus 6 years in one line. Tried:
aus_livestock$Month |> max() |> as_date() |> -years(6)
Error: function '-' not supported in RHS call of a pipe
Then tried curly braces {}
:
aus_livestock$Month |> max() |> as_date() |> {. -years(6)}
Error: function '{' not supported in RHS call of a pipe
This does work:
x <- aus_livestock$Month |> max() |> as_date()
x - years(6)
[1] "2012-12-01"
But this involves saving an intermediary variable x. I'd prefer to do it in a oner if there's a way?
CodePudding user response:
We could use a lambda function
aus_livestock$Month |>
max() |>
as_date() |>
(\(x) x - years(6))()
[1] "2012-12-01"