How can I output the content of a [ADV] file with the cat command in the console?-CodePudding

I have a folder with files, would like to output the contents of the individual files in a loop, but it doesn't work. Unfortunately, the name is not given.

What I tried:

cat \[ADV]\ ...

But it doesn't work.

If I change the filename for example ABC then it works. What am I doing wrong?

Examples of files:

[ADV] DFN-CERT-2018-0399 PHP- Eine Schwachstelle ermöglicht einen Denial-of-Service-Angriff.eml
[ADV] DFN-CERT-2018-0409 PostgreSQL- Eine Schwachstelle ermöglicht die Eskalation von Privilegien.eml [ADV] 
DFN-CERT-2018-0422 Tor- Zwei Schwachstellen ermöglichen Denial-of-Service-Angriffe.eml

CodePudding user response：

Put the literal parts of the filename inside quotes, while keeping the * (the intended glob character) unquoted. Thus:

#!/bin/bash
for file in '[ADV] '*.eml; do
    echo "FILE = ${file}:"
    cat <"${file}"
    echo
done

...this prevents [ADV] from being treated as a glob expression that matches exactly one character, either A, D or V, which would be its meaning when unquoted.

CodePudding user response：

Something like this should work as a FOR/DO LOOP.

#!/bin/bash
MY_IFS=$IFS
IFS=$(echo -en "\n\b")

for file in `ls \[ADV\]\ *.eml`; do
    echo "FILE = ${file}:"; cat "${file}";
    echo;
done
IFS=$MY_IFS

The