Python lists into dictionary-CodePudding

I have two lists:

['Slovenia', 'Turkey', 'Ukraine', 'Ukraine', 'Turkey']

['BMW Slovenia', 'Tesla Turkey', 'Opel Ukraine', 'Ford Ukraine', 'Fiat Turkey']

And I need to turn them into a dictionary with a list, where a country can have more than one item.

I want my dictionary to look like this:

{
    'Slovenia': ['BMW Slovenia'],
    'Turkey': ['Tesla Turkey','Fiat Turkey'],
    'Ukraine':['Opel Ukraine','Ford Ukraine']
}

Thank you for your answers!

CodePudding user response：

You can use dictionary comprehension. Note that this works even if the lists are of different length:

l1 = ['Slovenia', 'Turkey', 'Ukraine', 'Ukraine', 'Turkey']
l2 = ['BMW Slovenia', 'Tesla Turkey', 'Opel Ukraine', 'Ford Ukraine', 'Fiat Turkey']
out = {k: [c for c in l2 if k in c] for k in set(l1)}

For your specific case, you can also use zip (because the list lengths match) and dict.setdefault:

out = {}
for k,v in zip(l1,l2):
    out.setdefault(k, []).append(v)

Output:

{'Slovenia': ['BMW Slovenia'],
 'Turkey': ['Tesla Turkey', 'Fiat Turkey'],
 'Ukraine': ['Opel Ukraine', 'Ford Ukraine']}

CodePudding user response：

Use zip to pair the two lists, and a collections.defaultdict to store the results

from collections import defaultdict

x = ['Slovenia', 'Turkey', 'Ukraine', 'Ukraine', 'Turkey']
y = ['BMW Slovenia', 'Tesla Turkey', 'Opel Ukraine', 'Ford Ukraine', 'Fiat Turkey']

result = defaultdict(list)
for key, val in zip(x, y):
    result[key].append(val)

print(result)
# {'Slovenia': ['BMW Slovenia'],
# 'Turkey': ['Tesla Turkey', 'Fiat Turkey'],
# 'Ukraine': ['Opel Ukraine', 'Ford Ukraine']}