How to format string to be a default datetime object-CodePudding

I am logging some stuff in a JSON file, I have a datetime object that I convert into a string so that I can log it in the JSON (it doesn't accept the datetime object).

import datetime

now = datetime.datetime()
jsonFile.dumps(now)
# Dumping datetime object as string into JSON holding my logs, I should note I'm not actually dumping the logs, I'm getting them from a different source and logging them but this is probably what the source did

print(jsonFile["time"].now)
# When I try to use .now for the datetime object, it recognizes it as a string rather than a datetime object

My question is how do I convert the datetime string back into a datetime object. I know about strptime, I just don't know what format would make it compatible with other datetime.now objects.

Any time I try to use strptime, I use the '(%Y, %m, %d, %H, %M, %S)' format and get this error:

ValueError: time data '2021-12-10 23:34:56.234000' does not match format '(%Y, %m, %d, %H, %M, %S)'

So what is the correct format for a default datetime object?

CodePudding user response：

It would help if you have provided the format of the datetime format you saving in the json file. However let assume your date is as "YYYY-MM-DD HH:MM:SS" format. The procedure is as follows,

from datetime import datetime
dt_string = "2021-12-11 09:15:32"

# Considering date is in yyyy/mm/dd format
dt_object1 = datetime.strptime(dt_string, "%Y-%m-%d %H:%M:%S")

make sure you're using strptime with correct syntax.