How do I update like dislike vote in database without throwing an error?-CodePudding

I'm making an online business jargon dictionary using MongoDB. I want to make it possible to vote terms up and down. I'm getting to grips with CRUD, but I'm a bit stumped on the syntax for updating part of a record.

I have this template:

    <div >
        <a href="{{url_for('like', entry_id=entry._id)}}">
        <i ></i></a>
    </div>

The logic is that when "like" is clicked, the code should pull "love_percent" from a dictionary, convert to integer (or provide value zero if not present), add 1, convert to string and update within the same ObjectID. This is the code I wrote for that route:


    @app.route("/like/<entry_id>")
    def like(entry_id):
        entry = mongo.db.jargon.find_one({"_id": ObjectId(entry_id)})
        value = int(entry["love_percent"][0])
        value  = 1
        value = str(value)
        entry.update_one({"_id": ObjectId(entry_id)},
            {"$set": {
                love_percent[0]: value
            }})
        return render_template("jargon.html")

I tried using just update or storing the integer but that seemed to fix it. A friend suggested update_one but I'm basically a bit confused and lost.

Can anyone suggest what I'm missing here or a better approach?

(I'm aware that this doesn't prevent multiple votes from the same user; that functionality can come later.)

The dictionary is being staged on Heroku here and I have pushed it through with the bug: http://jargon-unchained.herokuapp.com/get_jargon

I get the following Error on Traceback: AttributeError: 'dict' object has no attribute 'update_one'

The repository for this code is in Github: https://github.com/dandavies23/jargon-unchained

CodePudding user response：

As per my understanding of the question.

You need to change the following:

As you have only like an option right now

value = int(entry["love_percent"])

You are changing in the database, so use the following command.

mongo.db.jargon.update_one({"_id": ObjectId(entry_id)},
            {"$set": {
                "love_percent" : value
            }})

Do try and tell issues faced in the comments.

CodePudding user response：

Removed [0] which I thought wasn't a position but a default integer. Resolved issue giving each entry a default of 55 on data-entry.

I was also re-rendering the template with a term I hadn't defined within the function. Fixed with a redirect.

def like(entry_id):
    entry = mongo.db.jargon.find_one({"_id": ObjectId(entry_id)})
    value = int(entry["love_percent"])
    value  = 1
    value = str(value)
    mongo.db.jargon.update_one({"_id": ObjectId(entry_id)},
        {"$set": {
            "love_percent": value
        }})
    return redirect(url_for("get_jargon"))