With Scala 2.12, I am looping an array with pattern matching to create a new array as below.
val arrNew=arrText.map {
case x if x.startsWith("A") =>x.substring(12, 20)
case x if x.startsWith("B") =>x.substring(21, 40)
case x => "0"
}.filter(_!="0")
If an element matches one of the two patterns, a new element is added into the new array arrNew
. Those that do not match will be dropped. My codes actually loop arrText
twice with filter. If I do not include case x =>"0"
, there will be errors complaining some elements are not getting matched. Are the codes below the only way of looping just once? Any way I can loop only once with case
matching?
map { x =>
if (condition1) (output1)
else if (condition2) (output2)
}
CodePudding user response:
you can use collect
[use case] Builds a new collection by applying a partial function to all elements of this sequence on which the function is defined.
val arrNew=arrText.collect {
case x if x.startsWith("A") =>x.substring(12, 20)
case x if x.startsWith("B") =>x.substring(21, 40)
}