How to handle conditional logic in Scala within the map function?-CodePudding

I got a small snippet of Scala code that I'd like to optimize to be more functional.

I got the following

val foo: Option[Double]
val bar: Map[String, Double]

And a method which takes an Option[Map[String, Double]]

So in my business logic, I try to determine if foo is defined. If it is, I have to pass None to the method, since both foo and bar cannot be simultaneously present.

I currently handle this in the following way

val newOptionalMap = if (foo.isDefined) {
      None
    } else {
      Some(bar)
    }
myFunction(newOptionalMap)

I'd like to turn this into a more functional approach. I tried with

val newOptionalMap = foo.map(_ => bar)

But this is failing, since it's never actually defining bar as None, thus my method fails as it doesn't expect both foo and bar to be simultaneously defined.

Which functional approach could I take to simplify the conditional logic?

CodePudding user response：

There are two way to handle your problem.

As stated by @jwvh you can easly used fold:

val newOptionalMap = foo.fold(Option(bar))(_ => None))

Another way could be using pattern matching:

val newOptionalMap = foo match {
   case Some(_) => None
   case _ => Some(bar)
}

Here there is a discussion about fold or pattern matching usage,