Python Selenium: If there are multiple "div" tags, how do print a specific one WITHOUT Xpa-CodePudding

I am trying to learn how to print by tag. Cannot use find element by xpath or class. If there are 4 "div" tags, how do I print the contents of a specific one?

Desired Output:

vjs-poster

Attempt 1:

divs = driver.find_elements(By.TAG_NAME, "div")
print(divs[0])

Attempt 2:

divs = driver.find_elements(By.TAG_NAME, "div")
print(divs[0].get_attribute('class'))

HTML: (The third line says "vjs-poster" this is what I want to print.)

<video id="video_html5_api"  onclick="streaming();" src="/video/stream?cntId=21671&amp;quality=sd"></video>
   <div></div>
   <div  tabindex="-1" style="background-image: url(&quot;https://[REDACTED].com/images/V15064/720X480/720x480/nt/4.jpg&quot;);"></div>
   <div  aria-live="assertive" aria-atomic="true"></div>
   <div  dir="ltr"></div>

CodePudding user response：

To print the value of the class attribute vjs-poster of the second <div> you can use:

print(driver.find_elements(By.TAG_NAME, "div")[1].get_attribute('class'))

You can also use a css_selector as:

print(driver.find_element(By.CSS_SELECTOR, "video.vjs-tech#video_html5_api  div  div").get_attribute('class'))

CodePudding user response：

You can try locating that element based on it class name and style or any one of them if the locator will still be unique.
You try this:

class_val = driver.find_elements(By.XPATH, "//div[contains(@style,'https://[REDACTED].com/images')").get_attribute('class')
print(class_val)