Alternating lines with Nested Loops-CodePudding

This is the exercise I need to complete: Using nested loops, write some code that outputs the following:

##########
**********
##########
**********
##########

Following is all the code I have so far. I assume I need to combine these two loop functions to one but I'm struggling with it. I'm early on in my first class and any help with this would be appreciated!

for a in range (0, 5, 2): 
    for b in range(10):
        print("#", end = "")
    print("")
for a in range (1, 5, 2):
    for b in range(10):
        print("*", end = "")
    print("")

CodePudding user response：

Since no input is specified, only a fixed output:

for _ in '_':
    for _ in '_':
        print('''##########
**********
##########
**********
##########''')

And yes, if that was my homework exercise, I'd absolutely submit this.

CodePudding user response：

I would suggest to simply base the symbol on the row index, even or odd

nb_lines = 5
line_size = 10

for i in range(nb_lines):
    for _ in range(line_size):
        if i % 2 == 0:
            print("#", end="")
        else:
            print("*", end="")
    print()

But no need of nested loops

nb_lines = 5
line_size = 10

for i in range(nb_lines):
    if i % 2 == 0:
        print("#" * line_size)
    else:
        print("*" * line_size)

CodePudding user response：

There are several ways to do it. First you should check how many lines you need to output. 5, so you need a loop doing something 5 times.

for i in range(5):

Now you need 2 loops to paste print the 2 line patterns (you already have them in your code)

 for b in range(10):
        print("#", end = "")
    print("")

and

for b in range(10):
        print("*", end = "")
    print("")

If you need to alternate between 2 values it's mostly the best to use the Modulo Operator.

So you can just switch between the 2 loops by % 2.

for i in range(5):
  if i % 2 == 0:
    for b in range(10):
        print("#", end = "")
    print("")
  else:
    for b in range(10):
        print("*", end = "")
    print("")

CodePudding user response：

def printStripes(row_length, number_of_rows):
    for _ in '_':
        print( "".join(
            [ "\n" if n%(row_length 1)==row_length else
              "#"  if (n//(row_length 1))%2==0 else
              "*"
              for n in range(number_of_rows*(row_length 1))
            ]
        ),end="")

printStripes(row_length=5,number_of_rows=8)

But don't tell your teacher that you got if from stackoverflow. (Thanks Kelly, for how to deal with the nested loop constraint.)

CodePudding user response：

You can use this to get the result that you want

for i in range(0,5):
     print("*"*10)
     print("#"*10)