Extraction the letter "C" using a regular expression I want only cells which begin with &q-CodePudding

I have the following code, I want the first if statement to be true only where r[18] < 6 and for the cells in column 14 which start with "C" I'm trying to use a regular expression to extract the first letter but unfamiliar using Regex. Can someone please assist. Thanks

  const ss = SpreadsheetApp.openById('10D0Qa8Y6nrAgeuS0V6-GyKkQBRooMUwseRc8agi7iN4');
  const sh = ss.getSheetByName("QUOTATIONS");
  const vs = sh.getRange(2, 1, sh.getLastRow() - 1, sh.getLastColumn()).getValues();
  const prod = sh.getRange(2, 14, sh.getLastRow() - 1, 1).getValues();
  RegExp(/^C/i,prod,0);
  
  vs.forEach((r,i) => {  if(r[18] < 6 && RegExp(/^C/i,prod,0))
    sh.getRange(i   2,33).setNumberFormat("0.#0").setValue((r[18] * r[19])   (r[21] * r[22])   (r[24] * r[25])   (r[27] * r[28])   (r[28] * r[31])  (6 - r[18]) * 20)
    vs.forEach((r,i) => { if(r[18] >= 6)
    sh.getRange(i   2,33).setNumberFormat("0.#0").setValue((r[18] * r[19])   (r[21] * r[22])   (r[24] * r[25])   (r[27] * r[28])   (r[28] * r[31]))
});
  }
  )}```

CodePudding user response：

If you need just a first letter you don't even need RegExp. It can be done with slice() this way:

var s = 'abc'

console.log(s.slice(0,1)) // output: 'a'

Or even:

var s = 'abc'

console.log(s[0]) // output: 'a'

If you want RegExp it can be string.match(/reg/) or /reg/.test(string):

var s = 'abc'

if (s.match(/^a/i)) { console.log('yes') } else { console.log('no') } // yes

if (s.match(/^b/i)) { console.log('yes') } else { console.log('no') } // no

if (/^a/i.test(s)) { console.log('yes') } else { console.log('no') } // yes

if (/^b/i.test(s)) { console.log('yes') } else { console.log('no') } // no