i need to make names that start with the letter K appear only in the console

let friends = ["keven", "Khaled", "keiven", 1, 2, "coder", "zein"];
let i = 0;
let counter = 0;


while (i < friends.length) {
    console.log(friends[i])
    i  
    if (friends[i][counter] === friends[i].includes("A")) {
        continue;
    }
}

CodePudding user response：

1. loop over the array
2. get the first letter as lowerCase
3. check if it equals to 'k'

    const friends = ["keven", "Khaled", "keiven", 1, 2, "coder", "zein"];
    for(let friend of friends){
        if(String(friend[0]).toLowerCase() === 'k'){
            console.log(friend);
        }
    }

CodePudding user response：

You can use the forEach syntax to cycle over your array, and then printing only the elements matching your request (so elements that are string and starts with a "k" letter).

friends.forEach((elem) => {
  if(elem.toString().toLowerCase().startsWith("k"))
    console.log(elem)
})