I need a regular expression to check that if a password contains:
- [1,6] uppercase/lowercase characters
- [1,10] digits
- [0,1] special characters
I tried multiple approach, but without success. I don't know if I can do this verify with regex. The most accurate pattern is : ^(?=(.*[a-zA-Z]){1,6})(?=(.*[0-9]){1,10})(?=(.*[!@#$%^&*()\-__ .]){0,1})
But it don't work good when I have more than 6 char, 10 digits or 1 special character.
Could anyone help me?
CodePudding user response:
I might not use a single regex pattern, but would instead use multiple checks. For example:
String password = "ABC123@";
int numChars = password.replaceAll("(?i)[^A-Z] ", "").length();
int numDigits = password.replaceAll("\\D ", "").length();
int numSpecial = password.replaceAll("[^!@#$%^&*()_ .-]", "").length();
if (numChars >=1 && numChars <= 6 && numDigits >= 1 && numDigits <= 10 &&
numSpecial <= 1) {
System.out.println("password is valid");
}
else {
System.out.println("password is invalid");
}