Taking the square root of each number in a list.

For this problem in the sqrt_list function:

1. Take the square root of each item in the list,
2. Store each squared item in another list, and
3. Return this list.

list(11,22,33) def sqrt_list(list): ret = [] for i in list: ret.append(i %) return ret

CodePudding user response：

Maybe this?

# Use this import for all examples
from math import sqrt

old = [1,2]
new = [sqrt(x) for x in old]

Function form

def sqrt_list(old):
    return [sqrt(x) for x in old]

or

def sqrt_list(old):
    new_list = []

    for i in old:
        new_list.append(sqrt(i))

    return new_list

Where:

print(sqrt_list([11, 22, 33]))

outputs:

[3.3166247903554, 4.69041575982343, 5.744562646538029]