I'm using a try/catch to make some fetch requests, then I am extracting the title from the HTML and adding it to my object 'sleekResponse' When I try to parse the body and add it to that object I'm having issues with the return value not including the title that I extracted from the HTML
I know this has something to do with asynchronicity, or my shallow understanding of Promises, but I can't tell why the return value is different from the value it's logging just before it's sent.
async function fetchUrl(url) {
console.log(url);
try {
const myInit = {
mode: 'cors'
}
let sleekResponse = {};
await fetch(url, myInit).then(function (response) {
sleekResponse.redirected = response.redirected;
sleekResponse.status = response.status;
return response;
})
.then((response) => titleWait(response))
.then((res) => sleekResponse.title = res)
function titleWait(response) {
Promise.resolve(response.text()).then((res) => {
a = res.split('<title>');
b = a[1].split('</title>')
sleekResponse.title = b[0];
return sleekResponse;
})
console.log(sleekResponse);
return sleekResponse;
}
console.log(sleekResponse); // This logs the correct value
return sleekResponse; // when it's returned it doesn't show the title that was added
} catch (err) {
return `${err}`;
}
}
I've tried so many things I don't remember everything that I tried. I know that I'm missing something that might be obvious, but I still don't understand why the console.log value is different from the value returned one line later.
CodePudding user response:
The main issue is that titleWait
doesn't return its own promise:
function titleWait(response) {
return Promise.resolve(response.text()).then((res) => {
a = res.split('<title>');
b = a[1].split('</title>')
sleekResponse.title = b[0];
return sleekResponse;
})
console.log(sleekResponse);
return sleekResponse;
}
It's still a very convoluted way to write it. This is better:
async function titleWait(response) {
const res = await response.text());
const a = res.split('<title>');
const b = a[1].split('</title>')
sleekResponse.title = b[0];
return sleekResponse;
}
CodePudding user response:
i hope i can a litel help
this basic fetch();
const response = await fetch('your url')
const data = await response.json();
console.log(data);