I'd like to slice an arbitrary dimensional array, where I pin the first n
dimensions and keep the remaining dimensions. In addition, I'd like to be able to store the n
pinning dimensions in a variable. For example
Q = np.random.rand(3, 5, 2) # array to be sliced
s = np.array([0, 1]) # the pinned first n dimensions
Q[0, 1, ...] # this is what I want manually
Q[s, ...] # this doesn't do what I want: it uses both s[0] and s[1] along the 0th dimension of Q
Is there a clean way to do this?
CodePudding user response:
You could do this:
Q[tuple(s)]
Or this:
np.take(Q, s)
Both of these yield array([0.58383736, 0.80486868])
.
I'm afraid I don't have a great intuition for exactly why the tuple version of s
works differently from indexing with s
itself. The other thing I intuitively tried is Q[*s]
but that's a syntax error.
CodePudding user response:
I am not sure what output you want but there are several things you can do.
If you want the output to be like this:
array([[[0.46988733, 0.19062458],
[0.69307707, 0.80242129],
[0.36212295, 0.2927196 ],
[0.34043998, 0.87408959],
[0.5096636 , 0.37797475]],
[[0.98322049, 0.00572271],
[0.06374176, 0.98195354],
[0.63195656, 0.44767722],
[0.61140211, 0.58889763],
[0.18344186, 0.9587247 ]]])
Q[list(s)]
should work. np.array([Q[i] for i in s])
also works.
If you want the output to be like this:
array([0.58383736, 0.80486868])
Then as @kwinkunks mentioned you could use Q[tuple(s)]
or np.take(Q, s)