Python dictionary: pass multiple lists into dictionary as values-CodePudding

Apologize for what might seem like an easy one. I'm trying to take two python lists and assign them as values for a dictionary, with the keys defined to match the list characteristics. For example, a list with only upper case words would be values for a key called "upperCase" and a list with lower case words would map as values to another key in the same dictionary called "lowerCase". The lists I've already created by iterating over a string value, splitting them into a main list and then assigning them to new lists (if the index[0] position of the word is uppercase or lowercase. My lists are such:

combDict = {}
isUpCase = ["Hello", "Goodbye", "John", "Jack"]
islowerCase = ["my", "name", "is", "human"]

My key assignments are "Upper" and "Lower"

My goal is to make my dictionary as so:

combDict = {Upper:  Hello, Upper:  Goodbye, Upper:  John, Upper:  Jack, Lower:  my, 
Lower:  name, Lower:  is, Lower:  human}

I've tried a couple of dictionary comprehensions but I cannot seem to get it right. Thoughts? What direction should I go?

CodePudding user response：

In Python, Dictionary keys must be unique, meaning you can't have two keys with the same value. I am interested to know what you want to achieve with that dictionary so that we can propose better solutions to you.

CodePudding user response：

Dictionaries do not take duplicate keys, therefore your goal dictionary is not possible. One solution would be to make combDict as a dictionary with lists as values.

combDict[Upper] = isUpCase
combDict[Lower] = islowerCase

If you are using the dictionary to figure out is a word is upper or lower case, you could set the word as key and its state (upper or lower case) as value, see below

for el in isUpCase:
   combDict[el] = Upper
for el in islowerCase:
   combDict[el] = Lower