What this error mean : expression must have pointer to object type but it has type struct add

#include <stdio.h>
int i, n;
struct add_stock
{
char fullname[30];
int stocks;
char com_name[30];
int shares;
float price;
float total;
int totalmoney;

} add;
int main()
{

printf("Enter full name : ");
scanf(" %[^\n]s", add.fullname);
printf("Enter the no. of stocks you want to purchased : ");
scanf("%d", &n);
for (i = 0; i < n; i  )
{

printf("Enter the name of the company : ");
scanf(" %[^\n]s", add[i].com_name);

printf("Enter the no. of shares you want to purchased : ");
scanf("%d", &add[i].shares);

printf("Enter the price of each share : ");
scanf("%f", &add[i].price);

add.total = add.shares * add.price;

printf("Toatl money invested in this stock : ");
scanf("%f", &add[i].total);
}
printf("Total money invested : ");
scanf("%d", add.totalmoney);

return 0;
}

In question it's add_stock , not add stock , i write like this becoz it's not accepting question. So, i get error for "add" saying subscripted value is neither array nor pointer nor vector.

CodePudding user response：

To declare an array of strucuture, you need to define the variable as below,

struct add_stock
{
   char fullname[30];
   int stocks;
   char com_name[30];
   int shares;
   float price;
   float total;
  int totalmoney;

} add[20];

this makes the add as an array of add_stock elements. then you can access it as, add[0].total, add[1].price and so on.

If you want to declare an array that need to be having dynamic number of elements, you can do so as below.


 struct add_stock* arStock;

 //allocate memory to hold 10 elements
 arStock = (add_stock*)malloc( 10 * sizeof(struct add_stock));

 arStock[0]->total=10;  //access it with ->, instead of .