How do I make `foo[1] ==1; foo[1][2]==3; foo[1][2][3]==6` work in JavaScript?-CodePudding

How do I define foo to make the following code work correctly as expected (in JavaScript)?

foo[1]   1             // 2
foo[1][2]   1          // 4
foo[10][20][30]   1    // 61
foo[100][200][300]   1 // 601

This is an interview question I once met.

CodePudding user response：

This sounds like a new take on the old variadic chainable sum function puzzle, with proxy member access instead of function calls. The possible approaches are still the same though, and the … 1 gives away that they are looking for the valueOf solution. In the same vein, foo 1 would be 1 and foo/Number(foo) would be 0.

const handler = {
    get(target, propName, receiver) {
        if (typeof propName == 'string' && /^\d $/.test(propName))
            return sumProxy(target   parseInt(propName, 10));
        else
            return Reflect.get(target, propName, receiver);
    }
};
function sumProxy(value) {
    return new Proxy({
        valueOf() { return value; }
    }, handler);
}
const foo = sumProxy(0);

console.log(foo   1);                // 1
console.log(foo[1]   1);             // 2
console.log(foo[1][2]   1);          // 4
console.log(foo[10][20][30]   1);    // 61
console.log(foo[100][200][300]   1); // 601