How can I convert a string to dictionary in a manner where I have to extract key and value from same-CodePudding

I need to convert string to dictionary in a manner for example

str1 = "00001000-0009efff : a 00100000-656b2fff : b"

Output what I require is

dict1 = {'a':['00001000','0009efff'], 'b':['00100000','656b2fff']}

Note: str1 can have many more such c, d, e with range.

CodePudding user response：

You can do it with a regex:

import re

pattern = r'([\w\-] ) : ([a-z])'
out = {m[1]: m[0].split('-') for m in re.findall(pattern, str1)}

Explanation of the regex:

match combination of alphanumeric characters and dashes [\w-]
followed by a space, a colon and a space _:_
followed by a character [a-z]

The groups are catching your relevant infos.

CodePudding user response：

Assuming you only have a single key letter for each value

str1 = str1.replace(" : ", ":").split(" ")
output = {}
for _, s in enumerate(str1):
    output[s[-1]] = s[:-2].split("-")

CodePudding user response：

This code will work in general

str1 = "00001000-0009efff : a 00100000-656b2fff : b"
needed_dictionary = dict()
split_string = str1.split()

for i in range(len(split_string)):
if split_string[i] == ":":
    needed_dictionary[split_string[i 1]]= split_string[i-1].split("-")
    
print(needed_dictionary)

But in Case the values or keys have "-" or ":" in them then this will fail.