Plotting nested lists seperately, which are inside nested dictionaries-CodePudding

I have a list consisting of multiple nested dictionaries and nested lists

MyList = [{dict0}, {dict1}, {dict2} ... {dict2422}]

dict0 = {'type': 'Feature', 'geometry': {'type': 'Polygon', 'coordinates': [[[1, 2], [1, 2], [ [3, 4], [3, 4]]]}}
dict1 = {'type': 'Feature', 'geometry': {'type': 'Polygon', 'coordinates': [[[1, 2], [1, 2], [ [3, 4], [3, 4]]]}}

I have tried the following by help from comments:

coords = sum((x['coordinates'] for item in features if 'coordinates' in (x :=item.get('geometry',{}))),start=[])

which results in:

coords = [[[1, 2], [1, 2]],
          [[3, 4], [3, 4]],
          [[5, 6], [5, 6]]]

I want to plot these lists seperately from eachother so:

coords1 = [[1, 2], [1, 2]]
coords2 = [[3, 4], [3, 4]]
coords3 = [[5, 6], [5, 6]]

and then plotting the first row of coords1 as x coordinate, second row as y coordinate. And then do the same for coords2. The entire coords list consists of ~2244 lists like this, each list of seperate landmass coastline xy coordinates, so coords1 is landmass 1, which is why the coords1 and coords2 need to be plottet independently

I tried to combine all the first elements of each lists and second elemnts of each lists to each their own new list

flatlist = [el for lst1 in coords for lst2 in lst1 for el in lst2]
x, y = flatlist[0::2], flatlist[1::2]

But plotting this just gives connecting lines between landmasses coastlines as its just 2 long lists of coordinates.

So how do I seperate the original coordslist into multiple lists, coords1, coords2, coords3 and so fourth, and then plot it? I know simple plots, but the coords has ~2244 lists in it and don't how to plot it without making 2244 lines of code. I assume a looped plot but I don't know how to. The coords list does not need to be seperated if plotting directly from it is possible.

CodePudding user response：

I belive this is what you are looking for,

a=[]
b=[]
for dic in MyList:
    for i in range(len(dic["geometry"]["coordinates"])):
        a.append(dic["geometry"]["coordinates"][i][0])
        b.append(dic["geometry"]["coordinates"][i][1])

CodePudding user response：

Perhaps something like

coords = sum((item['geometry']['coordinates'] for item in MyList), start=[])

A "safe" version would be

coords = sum((x['coordinates'] for item in MyList if 'coordinates' in (x := item.get('geometry', {}))), start=[])

The standard idiom for transposing a list afterwards is

x, y = zip(*coords)