`magrittr` pipe into apply-CodePudding

How do you pipe an object into a specific place in an apply call, that isn't the first input? The magrittr dot placeholder does not seem to work for this.

  dat <- 1:10 
  locs <- list(c(1, 2),
               c(3, 4),
               c(5, 6))
  
  foo <- function(x, y, z) {
    out <- mean(c(x[y], x[z]))
    return(out)
  }
  
  # works
  lapply(locs, function(z) foo(dat, z[1], z[2]))
  
  # none of these work 
  dat %>%
    lapply(locs, function(z) foo(., z[1], z[2]))
    
  dat %>%
    lapply(locs, function(z) foo((.), z[1], z[2]))
    
  dat %>%
    lapply(locs, function(z) {. %>% foo(z[1], z[2])})
    
  
  # New native pipe and placeholder also do not work
  dat |>
    lapply(locs, function(z) foo(_, z[1], z[2]))

CodePudding user response：

You can use {} like below

>   dat %>%
      {lapply(locs, function(z) foo(., z[1], z[2]))}
[[1]]
[1] 1.5

[[2]]
[1] 3.5

[[3]]
[1] 5.5

CodePudding user response：

Here are two ways, with the magrittr and native pipes.

suppressPackageStartupMessages(library(magrittr))
dat <- 1:10 
locs <- list(c(1, 2),
             c(3, 4),
             c(5, 6))

foo <- function(x, y, z) {
  out <- mean(c(x[y], x[z]))
  return(out)
}

# wrap the function around parenthesis
dat %>%
  (\(d) lapply(locs, \(z) foo(., z[1], z[2])))()
#> [[1]]
#> [1] 1.5
#> 
#> [[2]]
#> [1] 3.5
#> 
#> [[3]]
#> [1] 5.5

# New native pipe with anonymous function
dat |>
  {\(d) lapply(locs, \(z) foo(x = d, z[1], z[2]))}()
#> [[1]]
#> [1] 1.5
#> 
#> [[2]]
#> [1] 3.5
#> 
#> [[3]]
#> [1] 5.5

^{Created on 2022-05-18 by the reprex package (v2.0.1)}