javascript if solution if x is greater than any of the array numbers-CodePudding

need a little help please for a solution I have an array numbers and 2 vars. if x is greater than any of the array numbers,then y becomes the next number...

var x = 9
var y = 0
var array = [8,12,16,20,24,28,32]

ex
x = 9
y = 12

ex
x = 17
y = 20

ex
is equal...
x = 24
y = 24

CodePudding user response：

Here is a one-line function variable that returns what you want or 0 if no no value in the array is greater than x.

const array = [8 ,12 ,16, 20, 24, 28, 32]

const getY = (x) => (array.find(elem => elem >= x) || 0)

console.log(getY(17)) // 20

CodePudding user response：

Use this function .

`function findY(x,array){
for(var i=0;i<array.length;i  )
{
if(x<=array[i]){
    y=array[i]
    return y
}
    }}

findY(x,array)`

CodePudding user response：

Well its not a 1 line function but it does in an easy explanatory way.

var x = 24
var y = 0
var array = [8,12,16,20,24,28,32]

for (let step = 0; step < array.length; step  ) { 
  if(x==array[step]){
    y=x
   }else if(x>array[step] && step 1 <array.length ){  
    y = array[step 1];
   }
    
}
console.log(x,y)