Python list index multiple similar occurrences-CodePudding

This is my list:

text = ['direction','languag','mate','lan','diretion','diretions','non,'Diretion']

Using text.index(), how can I find the positions of words that are equal or similar to "direction" i.e diretion,diretions,Diretion ?

this is not an optimal solution:

[text.index("direction"),text.index("diretion"),text.index("diretions"),text.index("Diretion")]

I think that using a dictionary of similar words is an option but I don't know how to implement it. Please help

CodePudding user response：

We will do something like this, Please read how to implement dictionaries, it'd help you understand better

text = ['direction','languag','mate','lan','diretion','diretions','non','Diretion']
# making a dictionary with desired words
myDict = {'direction':1, 'diretions':1,'Diretion':1,'diretion':1}
# storing the answers in ans array
ans = []

and then you can run a for loop to get indices

for j in range(len(text)):
    if text[j] in myDict:
        ans.append(j)

CodePudding user response：

The index() method return the index of an element specified by value, otherwise it raise the exception ValueError (that you should handle with the try-except construct).

So, if you pass as a parameter a value similar, but which isn't contained in the list, you would get a ValueError exception.
The only way to do that is that you design and develop your own algorithm without rely on the index() method, which is useless, as I said.

A dictionary would be useless too, unless you find it a use in your own algorithm.

CodePudding user response：

You can use iterator enumerate(text) to get the index of each word in the list and then filter our all similar words which will give index of filtered words

text_index = [index for index, word in enumerate(text) if word in ("direction","diretion","directions")]