Is there a way to deserialize Json into Kotlin data class and convert property types?-CodePudding

I have some json

{ 
    "name": "Foo",
    "age": 12,
    "id": "1234567890"
}

Currently, my data class I want to deserialize into looks like this

data class Example( val name: String, val age: Int, val id: String)

Is there a way to simply have the data class as

data class Example( val name: String, val age: Int, val id: Long)

Attention to the id type Long

I suppose this can be achieved through the use of an extension function that parses the data class into a separate data classes.

But I'd like to know if this is possible in any other way. I'm using Jackson for deserialization.

CodePudding user response：

You don't have to do anything. Jackson automatically converts the String into a Long if it is possible:

import com.fasterxml.jackson.module.kotlin.jacksonObjectMapper
import com.fasterxml.jackson.module.kotlin.readValue

data class C(
    val s: String,
    val n: Long
)

fun main() {
    val json = """{"s":"My string","n":"1234567890"}"""

    val mapper = jacksonObjectMapper()
    val c: C = mapper.readValue(json)
    println(c)  // prints "C(s=My string, n=1234567890)"
}