How to pass the keyword for another funtion's argument within a new decorator?-CodePudding

def machines(machine_name):  
  rb = np.array(machines_file.loc[machines_file['Machine'].str.contains(machine_name), 'Resolved By'])
  rb_o = np.count_nonzero(rb == 'Outsource')
  rb_ih = np.count_nonzero(rb == 'In-House')
  return render_template('reachtruck.html',outsource=rb_o, inhouse=rb_ih)

#Passing a keyword for the argument of above funtion
@app.route('/home/reach_truck')
machines('Reach Truck')

The code is showing error of indentation when I am passing the keyword under the flask decorator

CodePudding user response：

The decorator goes on the function definition, not the function call:

@app.route('/home/reach_truck')
def machines(machine_name):  
    rb = np.array(machines_file.loc[machines_file['Machine'].str.contains(machine_name), 'Resolved By'])
    rb_o = np.count_nonzero(rb == 'Outsource')
    rb_ih = np.count_nonzero(rb == 'In-House')
    return render_template('reachtruck.html',outsource=rb_o, inhouse=rb_ih)

machines('Reach Truck')

If you want to only apply the decorator to that specific invocation of the function, don't use the decorator syntax, just call it as a normal function (note: I'm not a Flask expert but I don't think app.route will work as intended if you call it this way):

app.route('/home/reach_truck')(machines)('Reach Truck')

CodePudding user response：

decorator is basically a function. Just pass to it

app.route('/home/reach_truck')(machines)('Reach Truck')