I'm writing a test to assert that a function panics on invalid input, but Ginkgo records the panic as a failure instead of a passing result as expected.
func ParseUnixTimeString(unixTimeString string) time.Time {
i, err := strconv.ParseInt(unixTimeString, 10, 64)
if err != nil {
panic(fmt.Sprintf("could not parse time: %s", err.Error()))
}
return time.Unix(i, 0)
}
func TestFormat(t *testing.T) {
gomega.RegisterFailHandler(ginkgo.Fail)
ginkgo.RunSpecs(t, "Format Suite")
}
var _ = ginkgo.Describe("Format Tests", func() {
ginkgo.Describe("When formatting the date", func() {
ginkgo.It("should panic if the time can't be formatted", func() {
gomega.Expect(
tools.ParseUnixTimeString("2314321432143124223432434")).To(gomega.Panic())
})
})
Which returns (condensed):
•! [PANICKED] [0.002 seconds]
[It] should panic if the time can't be formatted
Test Panicked
could not parse time: strconv.ParseInt: parsing "2314321432143124223432434": value out of range
Ran 1 of 1 Specs in 0.002 seconds
FAIL! -- 0 Passed | 1 Failed | 0 Pending | 0 Skipped
How do I properly test for panics in Ginkgo/Gomega?
CodePudding user response:
From the documentation:
succeeds if ACTUAL is a function that, when invoked, panics. ACTUAL must be a function that takes no arguments and returns no result -- any other type for ACTUAL is an error.
Notice that ACTUAL (the argument passed into Expect
) is supposed to be a function.
What Gomega will do in this case, is invoke that function and catch the panic so it can assert on it.
To fix your particular example:
var _ = ginkgo.Describe("Format Tests", func() {
ginkgo.Describe("When formatting the date", func() {
ginkgo.It("should panic if the time can't be formatted", func() {
gomega.Expect(func(){
tools.ParseUnixTimeString("2314321432143124223432434")
}).To(gomega.Panic())
})
})