Exporting each land use listed in a shapefile column as a distinct shapefile-CodePudding

I have a shapefile with a column (named "Type") that lists 10 different land use types (string). I am trying to export each specific land use type as a distinct shapefile so that I will have 10 shapefiles each of which containing data on one land use. I have written the code below, but it only exports one land use (the one that comes last alphabetically), and I am not able to figure out how to fix my code.

data = gpd.read_file('G:/My Drive/The effects of land use/Final_Land_Use_-_2015.shp')

use = data.Type.unique()
for Type in use:
    gdf = data[data.Type==Type]
    gdf.to_file("Desktop/LST/{Type}.shp")

CodePudding user response：

The problem you have is that you're not properly constructing the file path. You're trying to use python's string formatting, but you didn't use the "f" prefix.

data = gpd.read_file('G:/My Drive/The effects of land use/Final_Land_Use_-_2015.shp')

land_uses = data["Type"].unique()
for land_use in land_uses:
    gdf = data.loc[data["Type"] == land_use]
    gdf.to_file(f"Desktop/LST/{land_uses}.shp") # <-- see the f-prefix?

CodePudding user response：

Modified: I completely missed deleted the data filtering part in my earlier post , Hope this works for you (may not be the most the efficient code, could be more simplified). I assumed the land-use column is string type Note: i think its always best to write the spatial files in the different folder

import geopandas as gpd

file_path="G:/My Drive/The effects of land use/Final_Land_Use_-_2015.shp"  
data= gpd.read(file_path)
extnsion='.shp'

use = data.Type.unique() 
for test in use:
    gdf = data[data.Type==test]
    a = file_path   test   extnsion
    gdf.to_file(a)