I Want To Print The Next Item In A List After A Condition Is Met-CodePudding

I'm new to python and I'm iterating on a small starter project from a tutorial. It's a little word guessing game. I have a master list of hints for specific secret words and I want to print a hint and after a wrong guess print the next hint in line.

I'm wanting to accomplish this without using a bunch of if statements because I think there's gotta be a more efficient shorthand way of doing it.

    import random

secret_word_list = ["Duck"]
duck_hint_list = ["Hint: It's a bird", "Hint: it swims", "Hint: It loves to be in a row"]
secretWord = random.choice(secret_word_list)
guess = ""
guess_limit = 3
guess_attempts = 0
game_end = False

while guess != secretWord and guess_attempts != guess_limit:
    if secretWord == "Duck":
        if guess_attempts != guess_limit:
            print(random.choice(duck_hint_list))
    guess = (input("Guess the secret word: "))
    guess_attempts  = 1

if guess_attempts == guess_limit:
    print("YOU LOSE IDIOT")
else:
    print("You Win!")

As you can see I tried using random.choice but the obvious downside to that is it will print the same hint twice.

CodePudding user response：

Start with an index at 0, and use it to print a hint when needed. When you do print a hint, increment the index by 1.

If you want to cycle through the hints, potentially repeating them, use: index % len(duck_hint_list) as your index.

If you wish the hints to come up in random order, first use random.shuffle on duck_hint_list.

CodePudding user response：

# import random

secret_word_list = "Duck"
duck_hint_list = ["Hint: It's a bird", "Hint: it swims", "Hint: It loves to be in a row"]
# secretWord = random.choice(secret_word_list)
guess = ""
guess_limit = 3
guess_attempts = 0
game_end = False
i=0 #here i intialized zero
while guess != secret_word_list and guess_attempts != guess_limit:
    # if secretWord == "Duck":
        if guess_attempts != guess_limit:
           # print(random.choice(duck_hint_list))
           print(duck_hint_list[i])#indexing
        guess = (input("Guess the secret word: "))
        guess_attempts  = 1
        i =1#incrementing

if guess_attempts == guess_limit:
    print("YOU LOSE IDIOT")
else:
    print("You Win!")

there are some code which i commented that are not in use. if you want new hint each time they you should use indexing which i did above and i also commented the part which i updated.

CodePudding user response：

in the original code, some variables and statements were not in use so I didn't include them in the revised code. I solved the problem of printing a new item in the list by removing the already shown hint, that way it will prevent a repetition of the hint. Also, it is always easier to make your condition for a while loop one clear-cut condition so you can exit the loop easier. I hope this helps you.

import random

secret_word = "Duck"
duck_hint_list = ["Hint: It's a bird", "Hint: it swims", "Hint: It loves to be in a row"]
guess_limit = 3
guess_attempts = 0
game_end = True #while loop condition 

while game_end:
    hint = random.choice(duck_hint_list) #picking a random hint from hint list
    print(hint)
    duck_hint_list.remove(hint) #removing of already shown hint
    guess = (input("Guess the secret word: "))
    guess_attempts  = 1
    
    if guess_attempts == guess_limit:
        print("YOU LOSE IDIOT")
        game_end = False #while loop condition change (breaking the loop)
    elif guess.lower() == secret_word.lower() :
        print("You Win!")
        game_end = False #while loop condition change (breaking the loop)