How to get path to file while the name of file is not full in python-CodePudding

I'll try to describe the problem in a simple way.

I have a .txt file that I can not know the full name of it which located under constant path

[for example: the full name is: Hello_stack.txt, I only can give to function the part: 'Hello_']

the input is: Path_to_file/ 'Hello_' the expected output is: Path_to_file/Hello_stack.txt

How can i do that?

I tried to give a path and check recursively if part of my file name is exist and if so, to return it's path.

this is my implementation: [of course I'd like to get another way if it works]


def get_CS_R2M_METRO_CALLBACK_FILE_PATH():
    directory = 'path_of_file'
    file_name = directory   'part_of_file_name'
    const_path = Path(file_name)
    for path in [p for p in const_path.rglob("*")]:
        if path.is_file():
            return path

Thanks for help.

CodePudding user response：

You might retrieve the file list in your path and then select from the list based upon your partial file name. Here is a snippet of code to perform that type of function on a Linux machine.

import os

dir = '/home/craig/Python_Programs/GetFile'


files = os.listdir(dir)

print('Files--> ', files)

for i in files:
    myfile = 'Hello_'
    if (myfile[0:4] == i[0:4]):
        print('File(s) like \"Hello_\"-->', i)

When I executed this simple program over a directory/folder that had various files in the directory, here was the output to the terminal.

Una:~/Python_Programs/GetFile$ python3 GetFile.py 
Files-->  ['Hello_Stack.txt', 'Okay.txt', 'Hi_Stack.txt', 'GetFile.py', 'Hello_Stack.bak']
File(s) like "Hello_"--> Hello_Stack.txt
File(s) like "Hello_"--> Hello_Stack.bak

The literal value for your path would be different on a Windows machine. I hope this might provide you with a method to achieve your goal.

Regards.

CodePudding user response：

Using pathlib.Path make a Path object of the directory. Then use Path.glob with the pattern you are looking for.

from pathlib import Path

path = Path(r'c:\path.to.file')
pattern = 'hello_*.txt'
for p in path.glob(pattern):
    print(p)

To make the pattern dynamic use string formatting.

a = 'hello_'
pattern = '{}*.txt'.format(a)
# or
#f'{a}*.txt'