I have the following code:
if (len(circles[0, :])) == 5:
start = time.time()
if (len(circles[0, :])) == 1:
end = time.time()
print(str(timedelta(seconds=end-start)))
This is the output:
0:01:03.681325
And this is the output i am looking to achieve:
1:03
CodePudding user response:
If you rely on just the default string representation of a timedelta
object, you will get that format. Instead, you will have to specify your own formatting:
from datetime import timedelta
def convert_delta(dlt: timedelta) -> str:
minutes, seconds = divmod(int(dlt.total_seconds()), 60)
return f"{minutes}:{seconds:02}"
# this is your time from your code
dlt = timedelta(minutes=1, seconds=3, milliseconds=681.325)
print(convert_delta(dlt))
And with this you get this output:
1:03
CodePudding user response:
Based on wkl's answer, you could input the minutes, seconds, using int(input())
and milliseconds using float(input())
.