Why does this function return as 2-CodePudding

I was trying to understand write function and its capabilities, I tried to write a function that gives the output of 5 since 5*10 is 50 but I could only write 1 byte I assumed that the output would be 5. Why is it 2?

#include <unistd.h>
void ft_putchar(int c){
    write(1, &c, 1);
}    
int main(){
    ft_putchar(5 * 10);
}

CodePudding user response：

5 * 10 is 50. The character code 50 corresponds to the character 2 in ASCII. Therefore the output is 2 when interpreted as ASCII (or character code compatible to ASCII, such as UTF-8).

Also note that int has typically 4 (or 2) bytes. It looks like the first byte, which is written via the write function, contained the value 50 because it is less than 256 and you are using a little-endian machine.