The Formula to compute the sum from 1 to n: total = n * (n 1) / 2
Here is the code question: Write a function that computes the sum of all values between n and m, inclusive. Is there some way to use that formula, n, and m to get the answer? Think outside the box... You don't have to come up with a new formula; there's a way to use the existing one to solve it.
I still passed all of the tests by writing this code:
but how do I solve it using the specified formula?
function solution(n, m){
let numsArr = [];
for(i=n; i <= m; i ){
numsArr.push(i);
}
let initialValue = 0;
let sum = numsArr.reduce(
(previousValue, currentValue) => previousValue currentValue,
initialValue
);
return sum
}
console.log(solution(5,9));
CodePudding user response:
The formula you want is the difference between sum up to m
minus sum up to n-1
.
const sum = (a) => a * (a 1) / 2;
const mySum = (m, n) => sum(m) - sum(n - 1);
console.log(mySum(9, 5));
CodePudding user response:
The result is ((m - n) / 2 n) * (m - n 1)
.
First get the average
between m
and n
: ((m - n) / 2 n)
.
Then multiply it by the numbers count: (m - n 1)
.
const average = ((m - n) / 2 n)
const numbersCount = (m - n 1)
const result = average * numbersCount