I need to write generate_count function returns the function which returns the value increased by 1-CodePudding

I wrote the code which does the first part of task: it returns the count of calls of function

def counter():
    val = [0]
    def generate_count():
        val[0]  = 1
        return val[0]
    return generate_count

generate_count = counter()
print(generate_count())

But also I must be able to send start value of count into the func. As I know if u enter in ur function that u need to pass arguments then u are not be able to leave value blank. For example: If u write like this

def func1(n):

then you must pass one argument to make it work otherwise it wont work, so how to make it possible to work if u pass any arguments else if u don`t?

CodePudding user response：

Use a default value:

def func1(n=0):
   <code>

This function can be called with a parameter n, or it can be called without n. If you call the function like this:

func1()

The value of the parameter n will be set to 0, as you didn't specify a value.

CodePudding user response：

It would probably make more sense to use a builtin generator for this case.

def counter(n=0):
    while True:
        n  = 1
        yield n

generate_count = counter(1)
print(next(generate_count)) # > 2