Would appreciate some help in the below problem.
For the below xml:
<test>
<a>1232</a>
<a>1236</a>
<a>1239</a>
</test>
My goal is to return the first element only if all elements have the same value without taking the last character into account. Otherwise I want to throw some exception or return some hardcoded value. The example above should return 1232.
The example below should throw error because 123,113,123 ( values without last char) are not all equal. :
<test>
<a>1232</a>
<a>1136</a>
<a>1239</a>
</test>
What I have tried so far:
I know that I can get all elements as a collection of string by using
<xsl:variable name="all_As" select="/test/a"/>
I also know that I can loop through all_As and perform the transformation.
<xsl:for-each select="$all_As">
<xsl:value-of select="substring(current(), 1, string-length(current())-1))"/>
</xsl:for-each>
But what is not clear to me is how do I perform the operation while keeping the array in memory? Ideally I would want to have a variable $all_transformed_As which would hold the transformed version of the original array? Is this possible to do in xslt? Is there some easier way to perform what I want to do?
CodePudding user response:
Try something along the lines of:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/test">
<result>
<xsl:choose>
<xsl:when test="count(distinct-values(a/substring(., 1, string-length(.) - 1))) > 1">error</xsl:when>
<xsl:otherwise>
<xsl:value-of select="a[1]" />
</xsl:otherwise>
</xsl:choose>
</result>
</xsl:template>
</xsl:stylesheet>
Note that this could be a bit simpler if the length of the strings is known in advance.