So I have a list of x elements as such:
list = ['0001', '0002', '0003', '0004', '0005', '0006', '0007', '0008', '0009']
If a element is removed (ex: '0004'):
['0001', '0002', '0003', '0005', '0006', '0007', '0008', '0009']
How can I add an element base on the last value which in this case is '0009'?
['0001', '0002', '0003', '0005', '0006', '0007', '0008', '0009', '0010']
CodePudding user response:
You can just create a zero padded value adding 1 to to the numeric value at last using str.zfill
, then append to the list:
lst = ['0001', '0002', '0003', '0004', '0005', '0006', '0007', '0008', '0009']
print(lst.pop(3))
val = str(int(lst[-1]) 1).zfill(4)
lst.append(val)
print(lst)
OUTPUT:
0004
['0001', '0002', '0003', '0005', '0006', '0007', '0008', '0009', '0010']
CodePudding user response:
Slight modification to author code : @ThePyGuy
Just to dynamically define the padding of zero based on '0004'
Code :
lst = ['0001', '0002', '0003', '0004', '0005', '0006', '0007', '0008', '0009']
lng=len(str(lst[3]))
val = str(int(lst[-1]) 1).zfill(lng)
lst.append(val)
print(lst)
Incase any issue feel free to guide me