How would I go about adding a new line on the 10th term on this zybooks question

#include <stdio.h>

int main(void) {
    int n;
   
    scanf("%d", &n);
    printf("%d\t", n);
   
    while (n > 1) {
        if (n % 2 == 1) {
            n = 3 * n   1;
        }
        else {
            n = n / 2;
        }
 
        printf("%d\t",n);
    }
   
    printf("\n");

    return 0;
}

CodePudding user response：

This solution uses a counter variable i which increments until 10 is reached. Once it is reached a newline character (\n) is printed.

#include <stdio.h>

int main(void)
{ 
    int n, i = 0;

    scanf("%d", &n); 

    printf("%d\t", n);

    while (n > 1) { 

           i  ;

           (n % 2 == 1) ? (n = 3*n 1) : (n = n/2);

           if (i == 10) {
               i = 0;
               printf("\n");
           }
           else {  
               printf("%d\t", n);
           }
    } 

    printf("\n");

    return 0; 
}