I can't put "continue" command in a defination-CodePudding

let's say,

def sample():
    if a==1:
        print(a)
    else:
        continue

for i in language:
    a=i
    sample()

I want to use this function in a loop, but the "continue" command gives me an error because there is no loop. What can I do?

CodePudding user response：

Return a boolean from the function and based on the return value make continue or not because continue must be within a loop

CodePudding user response：

continue keyword in python is only available in for or while loops. Also block defined variables like a are not available on the global scope.

I don't know what you want to achieve but assuming your code, you want to extract a condition into a function, something like this:

def condition(a):
    return a == 1

def sample(a):
   print(a)

for i in language:
    a=i
    if condition(a):
       sample(a)
    else:
       continue

CodePudding user response：

It is because the scope of the function doesn't know we are in a loop. You have to put the continue keyword inside the loop

CodePudding user response：

continue keyword cannot be used inside a function. It must be inside the loop. There is a similar question here. Maybe you can do something like the following.


    language = [1,1,1,2,3]
    a = 1
    
    def sample():
        if a == 1:
            print(a)
            return False
        else:
            return True
    
    for i in language:
        if sample():
            continue
        else:
            a = i

OR something like this:


    language = [1,1,1,2,3]
    a = 1
    
    def gen(base):
        for item in base:
            if a == 1:
               yield a
            else:
                continue
    
    for i in gen(language):
        a = i
        print(a)