custom sort array of data base on value-CodePudding

I have Array like this

 array = [
 {name: '0:homdel', data: Array(3)},
 {name: '1:LOH', data: Array(5)}, 
 {name: '2:het', data: Array(5)},
 {name: '2:LOH', data: Array(5)},
 {name: '3-4:het', data: Array(5)},
 {name: '3-4:LOH', data: Array(5)} ,
 {name: '5-8:het', data: Array(5)},
 {name: '5-8:LOH', data: Array(5)},
 {name: '9 :het', data: Array(5)},
 {name: '9 :LOH', data: Array(5)}]

How can I sort the array so that the result will become:

 sort = 
[{name: '0:homdel', data: Array(3)},
{name: '1:LOH', data: Array(5)},
{name: '2:LOH', data: Array(5)},
{name: '3-4:LOH', data: Array(5)},
{name: '5-8:LOH', data: Array(5)},
{name: '9 :LOH', data: Array(5)},
{name: '2:het', data: Array(5)} ,
{name: '3-4:het', data: Array(5)},
{name: '5-8:het', data: Array(5)} ,
{name: '9 :het', data: Array(5)} ]

I have tried array.sort(customSort);

function customSort(a, b) {
  let [countA, nameA] = a.name.split(':');
  let [countB, nameB] = b.name.split(':');
  let nameComparison = nameA.localeCompare(nameB);
  let countComparison = parseInt(countA) - parseInt(countB);
  if (nameComparison == 0) {
    return countComparison;
  } else {
    return nameComparison;
  }
 }

but the result is not what I expected.

CodePudding user response：

Explanation in comments. Basically, remove the first element and sort the rest based on a custom tag.

let array = [
 {name: '0:homdel', data: Array(3)},
 {name: '1:LOH', data: Array(5)}, 
 {name: '2:het', data: Array(5)},
 {name: '2:LOH', data: Array(5)},
 {name: '3-4:het', data: Array(5)},
 {name: '3-4:LOH', data: Array(5)} ,
 {name: '5-8:het', data: Array(5)},
 {name: '5-8:LOH', data: Array(5)},
 {name: '9 :het', data: Array(5)},
 {name: '9 :LOH', data: Array(5)}]

const thesort = (arr) => {
  // first grab the obj that is not getting sorted
  let first = arr.shift();
  // add the sortable tag
  let narr = arr.map(a => ({ ...a,
    tag: a.name.split(":")[1]
  }))
    .sort((a, b) => b.tag.localeCompare(a.tag)) // sort it
    .map(a => { delete a.tag; return a }); // remove the custom tag
  narr.unshift(first)
  return narr
}

console.log(thesort(array))

CodePudding user response：

You could split the string and use some adjustments for the value.

const
    array = [{ name: '0:homdel', data: [] }, { name: '1:LOH', data: [] }, { name: '2:het', data: [] }, { name: '2:LOH', data: [] }, { name: '3-4:het', data: [] }, { name: '3-4:LOH', data: [] }, { name: '5-8:het', data: [] }, { name: '5-8:LOH', data: [] }, { name: '9 :het', data: [] }, { name: '9 :LOH', data: [] }];

array.sort(({ name: a }, { name: b }) => {
    const
        split = s => {
            let [value, text] = s.split(':');
        
            if (value.includes(' ')) {
                value = parseInt(value)   .1;
            } else if (value.includes('-')) {
                let v = value.split('-').map(Number);
                value = (v[0]   v[1]) / 2;
            }

            return { value, text };
        },
        aa = split(a),
        bb = split(b);
        order = { homdel: 1, LOH: 2, het: 3 };

    return order[aa.text] - order[bb.text] || aa.value - bb.value
});

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

CodePudding user response：

Try this:

const array = [ {name: '0:homdel'}, {name: '1:LOH'}, {name: '2:het'}, {name: '2:LOH'}, {name: '3-4:het'}, {name: '3-4:LOH'} , {name: '5-8:het'}, {name: '5-8:LOH'}, {name: '9 :het'}, {name: '9 :LOH'} ];

const sorted = array.sort(({ name: a }, { name: b }) => {
  if(b === '0:homdel') return 1;
  else if(a === '0:homdel') return -1;
  const [, nameA] = a.split(':'), [, nameB] = b.split(':');
  return nameB.localeCompare(nameA);
});

console.log(sorted);