Saving output in the same folder as the original script in Python-CodePudding

I run Run.py where I am calling File1.py which is located in another folder 1. How do I save the output of File1.py in 1.txt in the same folder in which it is located and not the folder in which Run.py is located?

Run.py is

import subprocess

print(subprocess.run(['python',rf'C:\\Users\\USER\\OneDrive - Technion\\Research_Technion\\Python_PNM\\Sept15_2022\\Test\\1\\File1.py']))

File.py is

import csv

A=1
B=2
C=A B
print(C)

with open('1.txt', 'w') as f:
    writer = csv.writer(f)
    print(C)
    f.writelines('R'  '\n')
    f.write(str(C))

CodePudding user response：

You can find the path of the currently running script with the __file__ variable. So something like this would probably work:

import os

current_dir = os.path.dirname(__file__)
filename = os.path.join(current_dir, "1.txt")

with open(filename, "w") as f:
  # rest of code goes here

CodePudding user response：

Just add concat the path where the file.py is located to that 1.txt. You can get the path where file.py is located by:

import os
file_py_path = os.path.dirname(os.path.realpath(__file__))

Explore os.path.join() to join paths, this way you will avoid problems related to diff filesystems.