I need help with this assignment.

I already tried something and I can include the code that I wrote so far.

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
    int i, j, n;

    cout << "Please enter the positive integer:";
    cin >> n;

    if (n < 0) {
        cout << "\nEntered integer is not positive! Please enter the positive integer:";
        cin >> n;
    }

    for (i = 1; i <= n; i  ) {
        for (j = 1; j <= n; j  ) {
            if (i == 1 || i == n || j == 1 || j == n) {
                cout << setw(n) << "*";
            }
            else {
                cout << setw(n) << " ";
            }
        }
        cout << endl << "\n";
    }
    
    return 0;
}

Thanks in advance!

CodePudding user response：

Assuming a 1x1 grid looks like this:

****
*  *
*  *
****

e.g., is not also dependent on the number inputted, I would use the following:

for (int i = 0; i < n * 3   1;   i) {
    cout << "*"; //First row with stars
}
cout << endl;
for (int i = 0; i < n;   i) {
    cout << "*"; //First column with stars
    for (int j = 0; j < n;   j) {
        cout << "  *"; //Empty box and closing star
    }
    cout << endl;
    cout << "*"; //First column with stars
    for (int j = 0; j < n;   j) {
        cout << "  *"; //Empty box and closing star
    }
    cout << endl;
    for (int j = 0; j < n * 3   1;   j) {
       cout << "*"; //Bottom row of box with stars
    }
    cout << endl;
}

This code is not tested but just quickly typed, it might not work, so be careful using it. Let me know if there are some problems.

CodePudding user response：

There are several issues in your implementation:

if (n < 0) {
    cout << "\nEntered integer is not positive! Please enter the positive integer:";
    cin >> n;
}

The above condition will validate the user input only once. If the user enter a negative number more than once, it will not be checked.

cout << endl << "\n";

This will cause two end of lines to be printed, which is not needed.

Here is a working program which does the required job:

int main()
{
    int n;

    cout << "Please enter the positive integer: ";
    cin >> n;

    while (n < 0) {
        cout << "\nEntered integer is not positive! Please enter the positive integer: ";
        cin >> n;
    }

    for (int i = 0; i <= (n*n); i  ) {
        for (int j = 0; j <= (n*n); j  ) {
            if (i == 0 || (i % n == 0) || (j == 0) || (j % n == 0)) {
                cout << setw(2) << "*";
            } else {
                cout << setw(2) << " ";
            }
        }
        cout << '\n';
    }
    return 0;
}

Here is the output from the program: