Given a dummy function as such:

#include "DigiKeyboard.h"
        
void setup() {
            
#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

}
        
   void loop() {

  DigiKeyboard.delay(2000);

     }

I tried to get the content of the Setup function between the brackets and I tried

/[setup] [(][a-zA-Z0-9=',] [)][{]\n(. ?)\n \s [}]/gs

To get the result I want

#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

The problem is that the code was not written correctly because it works in the Regex site

But it doesn't work with javascript code and I think the reason is

regex single line flag /s

I searched a lot and read on Stackoverflow and the answers are not appropriate for the situation

My Regex

So even though the code works there, it won't work with JavaScript

var string = `


#include "DigiKeyboard.h"

void setup(){

#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

}

   void loop() {

  DigiKeyboard.delay(2000);

     }
        

`;



const regex = new RegExp("[setup] [(][)][{]\n(. ?)\n \s [}]');

console.log(string.match(regex) == null);

CodePudding user response：

This regex extracts the content within { ... } of setup:

var string = `

#include "DigiKeyboard.h"

void setup(){

#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

}

   void loop() {

  DigiKeyboard.delay(2000);

     }
`;

const m = string.match(/\bsetup\s*\(\)\s*\{\s*([^\}]*)/);
console.log(m ? m[1] : '(no match)');

Explanation of regex:

• \b -- word boundary
• setup -- expect literal setup string
• \s*\(\)\s* -- scan over optional whitespace, (), whitespace
• \{\s* -- scan over opening { and optional whitespace
• ([^\}]*) -- capture group scanning over everything not a closing }

Note that this will fail if your setup function contains curly braces. In that case you would need a proper language parser, or a multi-step regex that annotates the nesting level of the curly braces, so that you can identify the proper closing brace of the function.