Comparing the Nth letter to Nth letters of multiple strings in python-CodePudding

I can't quite figure this one out.

I have multiple five letter long strings and I want to compare each of the letters of the strings to a single string, and then to know if any of the Nth letters of the strings are equal to the Nth letter of the string I'm comparing them to, like this:

string_1 = 'ghost'
string_2 = 'media'
string_3 = 'blind'

the_word = 'shine'

if the_word[0] == string_1[0] or the_word[0] == string_2[0] or the_word[0] == string_3[0] or the_word[1] == string_1[1] or the_word[1] == string_2[1]... and so on...
  print('The Nth letter of some of the strings is equal to the Nth letter of the_word')
else:
  print('None of the letters positions correspond')

If there are multiple strings I want to compare the if statement gets very long so there must be a better way of doing this.

I would also like to know what the corresponding letters are (in this case they would be H (string_1[1] == the_word[1]), I (string_3[2] == the_word[2]) and N (string_3[3] == the_word[3])

If there are more than one corresponding letters I would like the return to be list containing all of the letters.

Also I dont need to know if the corresponding letter was the first or whatever the letters position in the word is, only if there are any (and what) corresponding letters.

I find this kind of hard to explain so sorry for possible confusion, will be happy to elaborate.

Thank you!

CodePudding user response：

IIUC, you can get to what you want using zip -

base_strings = zip(string_1, string_2, string_3)
for cmp_pair in zip(the_word, base_strings):
    if (cmp_pair[0] in cmp_pair[1]):
        print(cmp_pair[0])

Output

h
i
n

CodePudding user response：

You can extract the logic to a dedicated function and call it over each character of the string to be checked:

string_1 = 'ghost'
string_2 = 'media'
string_3 = 'blind'

the_word = 'shine'

def check_letter(l, i, words):
    match = []
    for w in words:
        if w[i] == l:
            match.append(w)
    return match

for i in range(len(the_word)):
    l = the_word[i]
    print("checking letter: {}".format(l))
    match = check_letter(l, i, [string_1, string_2, string_3])
    if (len(match) > 0):
        print("found in: {}".format(match))
    else:
        print("found in: -")

The above code results in:

$ python3 test.py
checking letter: s
found in: -
checking letter: h
found in: ['ghost']
checking letter: i
found in: ['blind']
checking letter: n
found in: ['blind']
checking letter: e
found in: -

CodePudding user response：

Maybe this answers your question:

strings = ['ghost', 'media', 'blind']
the_word = 'shine'

for s in strings:
    check = []
    lett = []
    for i in range(len(s)):
        if s[i] == the_word[i]:
            check.append(i)
            lett.append(s[i])
    if check:
        print('The letters {0} (position {1}) of the string {2} match to 
        the word {3}'.format(lett,check,s,the_word))
    else:
        print('No match between {0} and {1}'.format(s,the_word))

CodePudding user response：

Well one straight forward way would be the following:

string_1 = 'ghost'
string_2 = 'media'
string_3 = 'blind'
string_4 = 'trenn'

the_word = 'shine'

string_list = [string_1, string_2, string_3]

duplicate_letters_list = []
for string in string_list:
    for i in range(5):
        if the_word[i] == string[i]:
            print(f'{i}th letter is in {string} is a duplicate')
            if the_word[i] not in duplicate_letters_list:
                duplicate_letters_list.append(the_word[i])
print(duplicate_letters_list)

Output

1th letter is in ghost is a duplicate
2th letter is in blind is a duplicate
3th letter is in blind is a duplicate

['h', 'i', 'n']