issue while understanding the map and input function python-CodePudding

i am trying to take a list from user input using below code

n=int(input())
list1=[]
for i in range(0,n):
   ele=list(map(int,input()))
   list1.append(ele)
print(list1)

as per my understanding for below input 3 23 23 33 this should give me [23,23,33], however I am getting [[2,3],[2,3],[3,3]] can anyone please help understanding the flow and working of the map and list function and what I am missing.

CodePudding user response：

This would get what you want:

n = int(input())
list1 = [
    int(input()) for _ in range(n)
]
print(list1)

CodePudding user response：

Map returns an iterator that applies function to every item of iterable, yielding the results

n=int(input())
list1=[]
for i in range(0,n):
   ele=list(map(int,input()))
   print(ele)  # new print added to demonstrate
   list1.append(ele)
print(list1)

#output
1  # If I give only 1 output, no matter how big or small the number is, It will be broken into digits
12345
[1, 2, 3, 4, 5] # first print inside the loop
[[1, 2, 3, 4, 5]] # second print outside the loop

here is the link for the official document

https://docs.python.org/3/library/functions.html#map

Input() function takes argument as a string. String is an iterable so, int() function will be applied to each element of the string.

CodePudding user response：

As map doc described:

Return an iterator that applies function to every item of iterable, yielding the results.

The mistakes as follows:

input() function get a string from your console standard input. And, string is an iterable type! So, list(map(int, "23")) will return a [2,3] list.
list1.append(list2) will get a nested list like [[2,3]].

To get your wished result, you may change ele=list(map(int,input())) to ele=int(input()).